IFTS implementação inicial diferente da rfts, com suporte à high order

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Petrônio Cândido de Lima e Silva 2016-10-20 11:57:59 -02:00
parent d0c7753b2b
commit 01cdf092eb

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ifts.py Normal file
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import numpy as np
from pyFTS import *
class IntervalFTS(hofts.HighOrderFTS):
def __init__(self,name):
super(IntervalFTS, self).__init__(name)
self.flrgs = {}
def getUpper(self,flrg):
ret = np.array([s.upper for s in flrg.RHS])
return ret
def getLower(self,flrg):
ret = np.array([s.lower for s in flrg.RHS])
return ret
def getSequenceMembership(self, data, fuzzySets):
mb = [ fuzzySets[k].membership( data[k] ) for k in np.arange(0,len(data)) ]
return mb
def forecast(self,data):
ndata = np.array(data)
l = len(ndata)
ret = []
for k in np.arange(self.order+1,l):
up = []
lo = []
# Achar os conjuntos que tem pert > 0 para cada lag
count = 0
lags = {}
combinations = 1
for instance in ndata[k-self.order : k]:
mb = common.fuzzyInstance(instance, self.sets)
tmp = np.argwhere( mb )
idx = np.ravel(tmp) #flatten
lag = {}
lag["id"] = count
lag["sets"] = idx
lag["memberships"] = [mb[ k ] for k in idx]
lag["count"] = len(idx)
lags[count] = lag
combinations = combinations * lag["count"]
count = count + 1
print(combinations)
# Build a tree exploring all possibilities
# Trace each path from leaf to roots and reverse path
# -------
#return lags
wflrgs = {}
# Gerar as permutações possíveis e as FLRG's correspondentes
lag_inc = [0 for k in np.arange(0,self.order) ]
isComplete = False
while (isComplete):
flrg = hofts.HighOrderFLRG(self.order)
flrg.appendLHS( self.sets[ lag_inc[0] ] )
for lag_count in np.arange(1,self.order):
if lag_count > 1: lag_inc[ lag_count - 1 ] = 0
# for
#lag_count = lag_count + 1
# Achar a pert geral de cada FLRG
# achar o os bounds de cada FLRG
# gerar o intervalo
# tmpdata = common.fuzzySeries(XX,self.sets)
# tmpflrg = HighOrderFLRG(self.order)
# for s in tmpdata: tmpflrg.appendLHS(s)
# if tmpflrg.strLHS() not in self.flrgs:
# ret.append(tmpdata[-1].centroid)
# else:
# flrg = self.flrgs[tmpflrg.strLHS()]
# mp = self.getMidpoints(flrg)
# ret.append(sum(mp)/len(mp))
# return ret